Lesson 30--Microduino 8*8 Lattice Animated Emoticon
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Revision as of 08:59, 8 July 2016 by 172.31.23.3 (talk)
| Language: | English • 中文 |
|---|
ObjectiveThis tutorial will teach you display a changeing smiling face based on the static one. Equipment
8*8 lattice LED is：LD-1088BS, the following is its pin definition： Schematic
Program//Connect to 74HC595的ST_CP
int latchPin = 8;
//Connect to 74HC595的SH_CP
int clockPin = 12;
//Connect to 74HC595的DS
int dataPin = 11;
//Set the timer
unsigned long time;
//Hide line definition
byte masks[8]={
B01111111,B10111111,B11011111,B11101111,B11110111,B11111011,B11111101,B11111110};
//Action definition for smiling face
byte rows[2][8]={
{
B00111100,B01000010,B10100101,B10000001,B10100101,B10011001,B01000010,B00111100 }
,
{
B00111100,B01000010,B10100101,B10000001,B10111101,B10000001,B01000010,B00111100 }
};
void setup() {
//Baud rate 9600
Serial.begin(9600);
//Set latchpin as output
pinMode(latchPin, OUTPUT);
}
void loop() {
//Action change
for(int j=0;j<2;j++) {
unsigned long startTime = millis();
for (unsigned long elapsed=0; elapsed < 1000; elapsed = millis() - startTime) {//Display 600ms
for(int i=0;i<8;i++) {
digitalWrite(latchPin, 0);
shiftOut(dataPin, clockPin, masks[i]); //mask(col)
shiftOut(dataPin, clockPin, rows[j][i]); //row
digitalWrite(latchPin, 1);
}
}
//time=0;
}
}
void shiftOut(int myDataPin, int myClockPin, byte myDataOut) {
// This shifts 8 bits out MSB first,
//on the rising edge of the clock,
//clock idles low
//internal function setup
int i=0;
int pinState;
pinMode(myClockPin, OUTPUT);
pinMode(myDataPin, OUTPUT);
//clear everything out just in case to
//prepare shift register for bit shifting
digitalWrite(myDataPin, 0);
digitalWrite(myClockPin, 0);
//for each bit in the byte myDataOut�
//NOTICE THAT WE ARE COUNTING DOWN in our for loop
//This means that %00000001 or "1" will go through such
//that it will be pin Q0 that lights.
for (i=7; i>=0; i--) {
digitalWrite(myClockPin, 0);
//if the value passed to myDataOut and a bitmask result
// true then... so if we are at i=6 and our value is
// %11010100 it would the code compares it to %01000000
// and proceeds to set pinState to 1.
if ( myDataOut & (1<<i) ) {
pinState= 1;
}
else {
pinState= 0;
}
//Sets the pin to HIGH or LOW depending on pinState
digitalWrite(myDataPin, pinState);
//register shifts bits on upstroke of clock pin
digitalWrite(myClockPin, 1);
//zero the data pin after shift to prevent bleed through
digitalWrite(myDataPin, 0);
}
//stop shifting
digitalWrite(myClockPin, 0);
}Define two expression in rows[2][8]. DebugStep 1：Copy the code to IDE and compile it Step 2：Set up circuit, as follows： In order to protect the circuit, plus a 220Ω registor on the every connection line (total 8 lines) between one 74HC595 chip and 8*8 latteice LED. In our example, we don't use the registor, so the LED's brightnees is strong. If the lattice's quality is bad and easily broken. Step 3：Run program ResultThe expression will be changed on 8*8 8*8 lattice LED Video |
